(sina+cosa) ^2-1/tga-sina cosa+2 помогите пожалуйста

(sin (2)*sin (a) ^3+(2-cos (2)*cos (a)*sin (a) ^2+sin (a) -cos (a) /sin (a) Ответ: -sin (4*a+2) / (4*cos (2*a) -4)+3*sin (2*a+2) / (4*cos (2*a) -4) -sin (2*a-2) / (4*cos (2*a) -4)+sin (4*a) / (2*cos (2*a) -2) -3*sin (2) / (4*cos (2*a) -4)+cos (2*a) / (cos (2*a) -1) -1/ (cos (2*a) -1)