1) (12/41) ^x/26+1=(51/44) ^x/26+1 2) (7/8) ^ (x-1) /2=²⁶√8/7 3) 8=1/ (4^26x+1) Решите пожалуйста!) Спасибо…

(12/41) ^ (x/26)+1=(51/44) ^ (x/26)+1, (12/41) ^ (x/26)=(51/44) ^ (x/26) , (12/41*44/51) (x/26)=1, (176/697) ^ (x/26)=1,x/26=0,x=0, (7/8) ^ (x-1) /2)=²⁶√8/7, (7/8) ^ (x-1) /2)=(7/8) ^ (-1/26) , (x-1) /2=-1/26,x-1=-1/13,x=12/13, 8=1/ (4^ (26x+1) , (2^ (-2) ^ (26x+1)=2^3,-2 (26x+1)=3,26x+1=-3/2,26x=-5/2,x=-5/52.