При каких n число 2^2^2^2… .^2+9 (n двоек) – простое?

F (a, b, с, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z)={k+2} {1 – (wz+h+j – q) 2 – (2n+p+q+z – e) 2 – (a2y2 – y2+1 – x2) 2 – ({e4+2e3}{a+1}2+1 – o2) 2 – (16{k+1}3{k+2}{n+1}2+1 – f 2) 2 – ({ (a+u4 – u2a) 2 – 1}{n+4dy}2+1 – {x+cu}2) 2 – (ai+k+1 – l – i) 2 – ({gk+2g+k+1}{h+j}+h – z) 2 – (16r2y4{a2 – 1}+1 – u2) 2 – (p – m+l{a – n – 1}+b{2an+2a – n2 – 2n – 2}) 2 – (z – pm+pla – p2l+t{2ap – p2 – 1}) 2 – (q – x+y{a – p – 1}+s{2ap+2a – p2 – 2p – 2}) 2 – (a2l2 – l2+1 – m2) 2 – (n+l+v – y) 2}.