1 вариант. 1. Найдите площадь треугольника АВС, если СВ=4100 м, угол А=32 градуса, угол…

1В1. S=0,5*AC*BC*Sin (C) По Т. Синусов: AC/Sin (B)=BC/Sin (A) B=180-120-32=28AC=(4100*Sin (28) /Sin (32) S=0,5*(4100*Sin (28) /Sin (32)*4100*Sin (120)=(4100) ^2*Sin (28)*Sin120) / (2*Sin (32)=6449 2. AB/Sin (C)=AC/Sin (B)=BC/Sin (A) 5/Sin (60)=AC/Sin (45)=BC/Sin (180-60-45) A=75AC=4,08 BC=5,577 3. AB^2=BC^2+AC^2-2*BC*AC*Cos (C) AB^2=3/16+0,36-2*(3*√3/20)*(-√3/2)=0,1875+0,36+0,45=0,9975AB=0,9987AB/Sin (C)=AC/Sin (B)=BC/Sin (A) 0,9987/Sin (150)=0,6/Sin (B)=0,4330/Sin (A) Sin (B)=0,6*Sin (150) /0,9987=0,3004B=17,5C=180-150-17,5=12,5