Разложите на множители выражение (2x-5) вквадрате-xвквадрате=(5x-2) вквадрате- (x-1)…

(2x-5) ^2-x^2=(2x-5-x) (2x-5+x)=(x-5) (3x-5) (5x-2) ^2- (x-1) ^2=(5x-2+(x-1) (5x-2- (x-1)=(5x-2+x-1) (5x-2-x+1)=(6x-3) (4x-1)=3 (2x-1) (4x-1) (4x+3y) ^2- (3x-4y) ^2=(4x+3y+(3x-4y) (4x+3y- (3x-4y)=(4x+3y+3x-4y) (4x+3y-3x+4y)=(7x-y) (x+7y) (2x-4y) ^2- (5x+y) ^2=(2x-4y+(5x+y) (2x-4y- (5x+y)=(2x-4y+5x+y) (2x-4y-5x-y)=(7x-3y) (-3x-5y)=- (7x-3y) (3x+5y)