Если f (x)=1/2x — 4x и g (x)=3/x+7, то найдите: а) f (1)+g (1)+g (-1/2). b) f (1/2)+1/8g (-1 /4. c) f (-2) -g (3). d) 4f (2)+3g…

Решение: а) f (1)=1/2*1-4*1=1/2-4=-3,5g (1)=3/1+7=10g (-0,5)=3/ (-0,5)+7=1f (1)+g (1)+g (-0,5)=-3,5+10+1=7,5b) f (1/2)=1/2*1/2-4*1/2=0,25-2=-1,75g (-1/4)=3/ (-1/4)+7=-12+7=-5f (1/2)+1/8g (-1/4)=-1,75+1/8*(-5)=-1,75-0,625=-2,375 c) f (-2)=1/2*(-2) -4*(-2)=-1+8=7g (3)=3/3+7=1+7=8f (-2) -g (3)=7-8=-1 d) f (2)=1/2*2-4*2=1-8=-7g (1/3)=3/1/3+7=9+7=164f (2)+3g (1/3)=4*(-7)+3*16=-28+48=20