3/[2x-y]-2/[x+4y]=1 & & 1/[2x-y]+4/[x+4y]=12

Система 3/[2x-y]-2/[x+4y]=1 /*2 и сложим со 2 уравнением 1/[2x-y]+4/[x+4y]=12 получим 3/[2x-y]-2/[x+4y]=17/ (2x-y)=14 |/7 => 1/ (2x-y)=2 => 4x-2y=1 => x=1/4+y/2Подставим выражение х во 1 е уравнение 3/[1/2+y-y]+2/[1/4+y/2+4y]=16-2/ (1/4+9y/2)=12/ (1/4+9y/2)=5 => (1/4+9y/2)=(1+18y) /42*4/ (1+18y)=58/ (1+18y)=51+18y=8/518y=3/5y=1/30Подставим в хх=1/4+1/60=16/60=4/15 {x=4/15 y=1/30