2sinx*cosx — 6 (sinx-cosx)+6=0 решите, плиз!

2sin (x)=cos (x -60) 2sin (x)=cos (x) cos (60)+sin (x) sin (60)=(1/2) cos (x)+[ sq rt (3) /2 ]sin (x) 2sin (x) — [sq rt (3) /2]sin (x)=(1/2) cos (x) [ (4 — sq rt (3) /2]sin (x)=(1/2) cos (x) [ 4 — sq rt (3) ]sin (x)=cos (x) tan (x)=1 / [4 — sq rt (3) ]x=arctan [ 1/ { 4 — sq rt (3) } ]x=23,8 degrees (1 dp) x plus 180 also satisfies the eqation ie x=23,8 and x=203,8 are the required solutions